Question

Has to be in Java programming language

Java Python mirrorLength We'll say that a "mirror" section in an array is a group of contiguous elements such that somewhere in the array, the same group appears in reverse order. For example, the largest mirror section in {1, 2, 3, 8, 9, 3, 2, 1} is length 3 (the {1, 2, 3} part). Return the size of the largest mirror section found in the given array. 3 mirrorLength([1, 2, 3, 8, 9, 3, 2, 1]) mirrorLength([1, 2, 1, 4]) 3 mirrorLength([7, 1, 2, 9, 7, 2, 1]) 2 Go ...Save, Compile, Run (ctrl-enter) public int mirrorLength(int[] a) { }

Answer 1

Answer: Hey! kindly find your solution below. Let me know if any issue. Thanks.

This java program has a method to find mirror length is a given array taking an array as a parameter and return mirror length. All possible screenshots of outputs screenshots are attached. If any prob comments me in the comment box.

Java Code:

import java.util.*;
class Main
{
//method to return mirror length in given array
public static int mirrorLength(int[] arr)
{
int len = arr.length;//find array length
int count= 0; //needed variables
int mirr = 0;

if(len==0)
{
return 0;
}
  
for (int i = 0; i < len; i++) //loop to array length
{
count=0;
//to check mirror elements
for (int k = len-1; i + count < len && k > -1; k--)
{
if(arr[i+count] == arr[k])//if found increment count
{
count++;
}
else
{
if (count > 0)//if count >0
{
mirr = Math.max(count,mirr);//find max and store into mirr variable
count = 0;
}
}
}
mirr = Math.max(count,mirr);//find max
}
return mirr;//return mirror length
}

public static void main(String []args)
{
int [] arr1 = {7,1,2,9,7,2,1};//array given to find mirror length
int ans;
ans = mirrorLength(arr1);//call method
System.out.println("Mirror Length: "+ans);
}
}

34 public static void main(String []args) 35 { 36 int [] arr1 = {1,2,3,8,9,3,2,1};//array given to find mirror Length int ans; mirrorLength(arr1);//call method 39 System.out.println("Mirror Length: "+ans); 40 } 41 37 38 ans = } input Mirror Length: 3

36 int [] arri {1,2,1,4};//array given to find mirror Length 37 int ans; 38 ans = mirrorLength(arri);//call method 39 System.out.println("Mirror Length: "+ans); 40 } 41 } 42 inpu Mirror Length: 3

37 35 36 int [] arri {7,1,2,9,7,2,1};//array given to find mirror Length int ans; 38 ans = mirrorLength(arr1);//call method 39 System.out.println("Mirror Length: "+ans); 40 } 41 } input 42 Mirror Length: 2