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8) The motor model for a 3-phase 480V 1750 RPM induction motor is shown below. Stray losses are 1000W. Assuming it is running

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page) Soluton Ann 0:01 j0.14 ve jo.14 0.01 V: 480 3116 в с- to full Load Speed 1450 RPM fi = 60H3 (for united State) 1750 = 1page2 (page 2 ZA = 0.017 j0.14 + 0.0% + jo.14) (16) 0.028 .. pan756744) 03357 +32.140 = 0.01+00.14+(-2.24 +5.7149) 0.357 +3.2(pages) o magnetization Current Ty: Ne j16 = 274.72 10:035 16/90* = 17.17 |-89.965 © air gap power (7) Pg=m IRF = 3x (979.25*o Terminal voltageV= 480 page) () Input power factor Stater current I, = 975.25|-48.58 power factor = cos 48.58 = 0.66 L99

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