Question

A new multi-storey building is proposed to come up in Sydney CBD with an available floor space area of 0.53 million square ft. The distribution of the available area is as follows: • Residential - 25% • Services - 47% • Retail - 10% • Remaining allocation to Government offices Determine the number of trip attractions to this new building. Round up the value to the nearest integer. Answer:

Please solve with in depth detail

Answer 1

So first lets calculate the floor space area for different lane uses.

So we get

FSA Residential Services Retail Govt offices 25% 47% 10% 18% 0.1325 0.2491 0.053 0.0954)

Assume the residential is all single family dwelling units. Assume that services is more of less light industrial. Assume retail is a shopping center ( land use code 820). So we have based on ITE the trip rate would be

AM (7-9) PM (4-6) Daily Rate unit Total In Out Total In Out ITE No. Land Use Description Residential 210 Single-Family Detached Housing 820 Shopping Center 110 General Light Industrial DU 9.44 0.74 25% 0.99 63% 37% 75% 3895 ksf 37.75 0.94 6296 3.81 529%) ksf emp. 4.96 3.05 22.59 7.45 0.70 0.52 3.34 1.10 88% 83% 75% ksf 12% 17% 25% 25% 0.63 0.49 1.71 0.71 13% 22% 25% 20% 87% 78% 75% 730 Government Office Building emp. 75% 80%

Lets compute the daily trip generation

For SFDU assume density = 3 to 4 units/acre

SFDU = .1325 million = .1325 * 10⁶/ 43560 = 3.042 acres

Assume density = 5 units/acre so we have 5 * 3.042 = 15 DU's

So we can get the daily trip generation like this

note that sq. ft shold be in 1000

15 Residential Services Retail Govt offices 25% 47% 10% 18% FSA ( million sq ft) FSA (ksf) Units 0.1325 132.5 0.2491 249.1 0.053 53 0.0954 95.4 Trip Rate Daily Trips 9.44 141.6 4.96 1235.536 37.75 2000.75 22.59 2155.086 5533

So total trips = 5533 but this is in + out

So attractions = 5533/2 = 2767 trips

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