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Subnet A Subnet B FO/6 PC-A Golo>< 601 R1 Fo/S PC-B $1 Develop the IPv4 Addressing Scheme Given an IP address and mask of 209
Subnetting Table: Sunt Subnet ma Prefix Network ID First Usable IP Last UsableP Broadcast IP Number of Hosts Points Number of
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Answer #1

Subnet-A
Number of Hosts = 40
Subnet Size = 64
Number of Usable hosts = 64-2 = 62
Subnet mask = 255.255.255.192
Prefix = /26
Network ID = 209.165.201.0
First Usable IP = 209.165.201.1
Last Usable IP = 209.165.201.62
Broadcast IP = 209.165.201.63

Subnet-B
Number of Hosts = 120
Subnet Size = 128
Number of Usable hosts = 128-2 = 126
Subnet mask = 255.255.255.128
Prefix = /25
Network ID = 209.165.201.128
First Usable IP = 209.165.201.129
Last Usable IP = 209.165.201.254
Broadcast IP = 209.165.201.255


Subnet-C
Number of Hosts = 5
Subnet Size = 32
Number of Usable hosts = 32-2 = 30
Subnet mask = 255.255.255.224
Prefix = /27
Network ID = 209.165.201.64
First Usable IP = 209.165.201.65
Last Usable IP = 209.165.201.94
Broadcast IP = 209.165.201.95

Subnet-D
Number of Hosts = 12
Subnet Size = 32
Number of Usable hosts = 32-2 = 30
Subnet mask = 255.255.255.224
Prefix = /27
Network ID = 209.165.201.96
First Usable IP = 209.165.201.97
Last Usable IP = 209.165.201.126
Broadcast IP = 209.165.201.127

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