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please help me complete this exam, i've work 12 hours per day, doing the 2nd/Grave yard shift, to raise my children.

i had no time to study to complete this exam.

please help me, thank you very very much.
Logical Physical x 651, y: 325 LAN-01: 100 hosts 296024TT Switch3 PC-PT PC3 LAN-05: 290 hosts LAN-03: 130 hosts PC-PT PCT 296
Step 1: Determine the number of subnets needed. You will subnet the network address 189.14.0.0 116. The network has the follo
h. Which subnet mask will accommodate the number of IP addresses required for the connection between Router 2 and Router 3 ?
If further subnetting is required, use this Extended table below. List a maximum of all sub-subnets as needed Sub - Subnet Ta
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Homework Answers

Answer #1

Subnet Name

Needed Size

Allocated Size

Address

Mask

Dec Mask

Assignable Range

Broadcast

Lan-05

290

510

183.14.0.0

/23

255.255.254.0

183.14.0.1 - 183.14.1.254

183.14.1.255

Lan-02

260

510

183.14.2.0

/23

255.255.254.0

183.14.2.1 - 183.14.3.254

183.14.3.255

Lan-04

175

254

183.14.4.0

/24

255.255.255.0

183.14.4.1 - 183.14.4.254

183.14.4.255

Lan-03

130

254

183.14.5.0

/24

255.255.255.0

183.14.5.1 - 183.14.5.254

183.14.5.255

Lan-01

100

126

183.14.6.0

/25

255.255.255.128

183.14.6.1 - 183.14.6.126

183.14.6.127

Lan-06

100

126

183.14.6.128

/25

255.255.255.128

183.14.6.129 - 183.14.6.254

183.14.6.255

Router 0

2

2

183.14.7.0

/30

255.255.255.252

183.14.7.1 - 183.14.7.2

183.14.7.3

Router 1

2

2

183.14.7.4

/30

255.255.255.252

183.14.7.5 - 183.14.7.6

183.14.7.7

Router 2

2

2

183.14.7.8

/30

255.255.255.252

183.14.7.9 - 183.14.7.10

183.14.7.11
Router 3 2 2 183.14.7.12 /30 255.255.255.252 183.14.7.13 - 183.14.7.14 183.14.7.15

Answer A
**************

126 hosts

Answer B
**************

510 hosts

Answer C
**************

254 hosts

Answer D
**************

254 hosts

Answer E
**************

510 hosts

Answer F
**************

126 hosts

Answer G
**************

2 Ips connection between router 0 and 1 1 and 2


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