Question

QUESTION 6 15 marks In this question you have to write a C++ program to convert a date from one format to another. You have to write a complete program consisting of amain () function and a function called convertDate(). The function receives a string of characters representing a date in American format, for example December 29, 1953. The function has to convert this date to the international format. For example: If the string December 29, 1953 is received, the string that the function should return must be 29 December 1953 Use the following C+ skeleton: include <iostream> #include <string> using namespace std; string convertDate........) 1 // Add the code for the function here 1 ITURN OVER 12 CO51511 MAY/JUNE 2020 int main() -- string americanDate: // Add the code for the main function here return 0 The main() function should prompt the user to enter the string, then read the string and call function convert Date to convert it to the required form, Hint 1 Below the question we list a number of stringmember functions you may need. Hint 2: Start the convertate function by determining the position of the first space character in the input

Answer 1

Code is as follows:

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#include <iostream>
#include<string>
using namespace std;

string convertDate(string americanDate){
int i = americanDate.find(" "); //find the first space
string Month = americanDate.substr(0,i); //get month
int k = americanDate.find(","); //find location of ","
string Day = americanDate.substr(i+1,k-i-1); //find day
  
string Year = americanDate.substr(k+2,americanDate.size()); //find year
  
string newDate = Day + " " + Month + " " + Year; //concatenate to get international format
return newDate; //return newDate
}
int main()
{
string americanDate;
  
cout<<"Enter the date in American format : "; //prompt for the americanDate
getline(cin,americanDate); //get americanDate
  
cout<<"Original date: "<<americanDate<<endl; //print americanDate
cout<<"Coverted date(to international format): "<<convertDate(americanDate)<<endl; //call the convertDate and print Coverted date
return 0;
}

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Screenshot of the code:

1 #include <iostream> 2 #include<string> 3 using namespace std; 4 5 6. string convertDate(string americanDate) { 7 int i = americanDate.find(" "); //find the first space 8 string Month americanDate.substr(0,i); //get month 9 int k = americanDate.find(","); //find Location of ", 10 string Day = americanDate.substr(i+1, k-i-1); //find day 11 12 string Year americanDate.substr(k+2, americanDate.size()); //find year 13 14 string newDate + Month + " " + Year; //concatenate to get international format 15 return newDate; //return newDate 16 } 17 int main() 18 { 19 string americanDate; 20 21 cout<<"Enter the date in American format : "; //prompt for the americanDate 22 getline(cin, americanDate); //get americanDate 23 24 cout<<"Original date: "<<americanDate<<endl; //print americanDate 25 cout<<"Coverted date(to international format): "<<convertDate(americanDate)<<endl; // call the convertDate and print Coverted date 26 return 0; 27 } 28 Day + -

Output:

Enter the date in American format : December 29, 1953 Original date: December 29, 1953 Coverted date(to international format): 29 December 1953 ... Program finished with exit code o Press ENTER to exit console. I