Question

QUESTION 6 15 marks In this question you have to write a C++ program to convert a date from one format to another. You have to write a complete program consisting of a nain() function and a function called convert Datel). The function receives a string of characters representing a date in American format, for example December 29, 1953. The function has to convert this date to the international format. For example: If the string December 29, 1953 is received, the string that the function should return must be 29 December 1953 Use the following CH skeleton: include <iostrean #include <string> using namespace std; string convert Date.....) // Add the code for the function here ITURN OVER] 12 CDS1511 MAY/IUNE2020 int main() string ameri canDate; // Add the code for the main function here return 0; } The main() function should prompt the user to enter the string, then read the string and call function convert Date() to convert it to the required form. Hint 1: Below the question we list a nurnber of stringmember functions you may need. Hint 2: Start the convert Date() function by determining the position of the first space character in the input. A number of stringmember functions to help you StringObject.si zel) StringObject.substristart Pos, length) StringObject find substring) StringObject. fi nd substring, start Pos) StringObject.insert(insert Pos, substring); StringObj ect.erasest art Pos, length); StringObj ect.replace(start Pos, length, substring): where start Pos, lengt hand insert Posine ol type i nt.and substring of type string.

Answer 1

Here is the answer for your question in C++ Programming Language.

CODE :

#include<iostream> #include<string.h> using namespace std; string convertDate(string americanDate){ //find the index of first space character int firstSpaceChar = americanDate.find(" "); //Extract month string month = americanDate.substr(0, firstSpaceChar); //Extract remaining sub string after month name string sub = americanDate.substr(firstSpaceChar + 1); //Find the index of second space character int secondSpaceChar = sub.find(" "); //Extract day string day = sub.substr(0,(secondSpaceChar-1)); //Extract year string year = sub.substr(secondSpaceChar + 1); //Converted Date americanDate.replace(0,americanDate.size(),(day + " " + month + " " + year)); //Return converted date return americanDate; } int main(){ string americanDate; //Read date cout << "Enter Amarican date : " ; getline(cin, americanDate); //Call Convert Date function string converted = convertDate(americanDate); //Display output cout << "International Date : " << converted << endl; return 0; }

SCREENSHOTS :

Please see the screenshots of the code below for indentations of the code.

1 8 14 15 convertDate.cpp #include<iostream> 2 #include<string.h> 3 using namespace std; 4 string convertDate(string americanDate) { 5 //find the index of first space character 6 int firstSpaceChar = americanDate.find(" "); 7 //Extract month string month = americanDate. substr(0, firstSpaceChar); 9 //Extract remaining sub string after month name 10 string sub = americanDate. substr(firstSpaceChar + 1); 11 //Find the index of second space character 12 int secondSpaceChar = sub.find(" "); 13 //Extract day string day = sub.substr(0,(secondSpaceChar-1)); //Extract year 16 string year = sub.substr(secondSpaceChar + 1); 17 //Converted Date 18 americanDate.replace(0, americanDate.size(), (day + + month + 19 //Return converted date 20 return americanDate; 21 22 int main() { 23 string americanDate; 24 //Read date 25 cout << "Enter Amarican date : ; 26 getline(cin, americanDate); 27 //Call Convert Date function 28 string converted = convertDate(americanDate); 29 //Display output 30 cout << "International Date : << converted << endl; 31 return ; 32 + year)); } مه

OUTPUT :

Enter Amarican date : December 29, 1953 International Date : 29 December 1953 Process exited after 16.64 seconds with return value o Press any key to continue

Enter Amarican date : July 01, 2020 International Date : 01 July 2020 Process exited after 8.417 seconds with return value o Press any key to continue

Any doubts regarding this can be explained with pleasure :)