Question

In this question you have to write a C++ program to convert a date from one format to another. You have to write a complete program consisting of a main() function and a function called convertDate(). The function receives a string of characters representing a date in American format, for example December 29, 1953. The function has to convert this date to the international format. For example: If the string December 29, 1953 is received, the string that the function should return must be 29 December 1953 Use the following C++ skeleton: include <iostream> #include <string> using namespace std; string convertDate (........) // Add the code for the function here

Answer 1

Below is the code in C++ for the above question:

#include<iostream>
#include<string>
using namespace std;

string convertDate(string americanDate){
   // creating string variables for extracting
   // month, day and year.
   string month = "",day = "",year = "";
   int pos;
   // finding pos of space
   pos = americanDate.find(' ');
   // finding month
   month = americanDate.substr(0,pos);
  
   // removing the month part from the americanDate
   americanDate = americanDate.substr(pos+1,americanDate.length()-month.length());
  
   // finding the pos of space.
   pos = americanDate.find(' ');
   // finding the day.
   day = americanDate.substr(0,pos - 1);
  
   // finallu finding the year
   year = americanDate.substr(pos+1,5);
  
   // constructing the converted date.  
   string convert = day + " " + month + " " + year;
   return convert;
}

int main(){
  
   string americanDate;
   // getting date from the user.
   getline(cin,americanDate);
  
   // calling convertDate function to convert the format
   string convertedDate = convertDate(americanDate);
   // displaying the converted date.
   cout << convertedDate;

   return 0;
}

Refer to the screenshot attached below to better understand the code and indentation:

#include<iostream> #include<string> using namespace std; string convertDate(string americanDate) { // creating string variables for extracting // month, day and year. string month = "", day , year = 1841 int pos; 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 // finding pos of space pos = americanDate.find(' '); // finding month month = americanDate. substr(0,pos); 1/ removing the month part from the americanDate americanDate = americanDate.substr(pos+1, americanDate.length() -month.length(); // finding the pos of space. pos = americanDate.find(' '); // finding the day. day = americanDate.substr(0,pos - 1); // finallu finding the year year = americanDate.substr(pos+1,5);




Output:

December 29, 1953 29 December 1953


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