Question

QUESTION 4 16 marks 4.1 4.2 Declare two integer constants ROWSIZE equal to 4 and COLSIZEequal to 4. Declare two inttwo-dimensional arrays, namely playlwith ROWSIZEnumber of rows and COLSIZEnumber of columns, and play with ROWSIZEnumber of rows and COLSIZEnumber of columns, (4) (4) 4.3 Assume that values have been assigned to all the elements of playland play. Also assume that an int variable trickyhas been declared and intialised to 0. Use nested forloops and write down the necessary C++ statements to do the following: Each row of playlis compared element by element to the corresponding row of play2. If the elements are equal, add the value of one element to tricky. If the elements are not equal, add the sum of the two elements to the value of tricky. For example, if playl and play2 are initialised as follows: 6 1 6 3 7 5 8 3 اليه الرما 7 8 5 5 and 4 5 8 7 3 7 6 4 2 8 5 7 3 5 respectively, then the value of tricky will be: 5+11+3+7+11+8+12+8+11+10+9+5+7+11+5+5=128 Display the value of tricky. Do NOT write a complete program or any functions. Write down ONLY the required statements. (8)

Answer 1

I WROTE THE CODE :

#include<conio.h>
#include <iostream>

using namespace std;

int main()
{
const int ROWSIZE=4,COLSIZE=4;

int tricky=0,i,j;
int sum;
  
int play1[ROWSIZE][COLSIZE]={{1,5,3,7},
{6,8,5,8},
{3,3,3,5},
{7,8,1,5}
};
int play2[ROWSIZE][COLSIZE]={{4,6,3,7},
{5,0,7,8},
{8,7,6,5},
{7,3,4,5}};
  

  
for(i=0;i<ROWSIZE;i++)
{
for(j=0;j<COLSIZE;j++)
{
if(play1[i][j]==play2[i][j])
{
tricky=tricky+play1[i][j];
}
else
{

sum=play1[i][j]+play2[i][j];
tricky=tricky+sum;
}
}
}
cout<<"The value of the tricky:"<<tricky;

return 0;
}

OUTPUT: