From the following equations, calculate ΔH for the reaction
From the following enthalpy changes in equations (1) and (2), calculate the heat of reaction for equation (3). (1) C(s) + 1/2 O2 (g) → CO (g) ΔH°= -110.5 kJ (2) CO (g) + 1/2 O2 (g) → CO2 (g) ΔH°= - 283.0 kJ (3) C(s) + O2(g) →CO2(g)
Use Hess' Law to calculate the ΔH for the following reaction from the data given below. Na2CO3(s) + 2HCl(aq) → 2NaCl(aq) + CO2(g) + H2O(l) ΔH = _________ Na2CO3(s) → CO2(g) + Na2O(s) ΔH = 319.8 kJ 2NaCl(aq) + H2O(l) → 2HCl(aq) + Na2O(s) ΔH = +348.0 kJ
Calculate ΔH for the following reaction, CaO(s) + CO2(g) → CaCO3(s) given the thermochemical equations below. 2 Ca(s) + O2(g) → 2 CaO(s) ΔH = -1270.2 kJ C(s) + O2(g) → CO2(g) ΔH = -393.5 kJ 2 Ca(s) + 2 C(s) + 3 O2(g) → 2 CaCO3(s) ΔH = -2413.8 kJ A compound contains C, H and O as the elements. A 20.0 g-sample is comprised of 1.34 g H and also 8.00 g of C. What...
Consider the following equations: 3A + 6B --> 3D ΔH = -403 kJ/mol E + 2F --> A ΔH = -105.2 kJ/mol C --> E + 3D ΔH = +64.8 kJ/mol Suppose the first equation is reversed and multiplied by 1/6, the second and third equations are divided by 2, and the three adjusted equations are added. What is the net reaction and what is the overall heat of this reaction
From the following enthalpy changes in equations (1) and (2), find the ΔH° for equation (3). (1) 2P(s) + 3Cl2(g) →2PCl3 (l) ΔH° = -640 kJ (2) 2P(s) + 5Cl2 (g) → 2PCl5 (s) ΔH° = -886 kJ (3) PCl3(l) + Cl2 (g) → 2PCl5 (s)
Consider the following equations. 3 A + 6 B → 3 D, ΔH = -440. kJ/mol E + 2 F → A, ΔH = -102.5 kJ/mol C → E + 3 D, ΔH = +64.5 kJ/mol Suppose the first equation is reversed and multiplied by 1/6, the second and third equations are divided by 2, and the three adjusted equations are added. What is the net reaction?
From the enthalpies of reaction 2C(s)+O2(g)→2CO(g)ΔH=−221.0kJ 2C(s)+O2(g)+4H2(g)→2CH3OH(g)ΔH=−402.4kJ calculate ΔH for the reaction CO(g)+2H2(g)→CH3OH(g)
Calculate the value of ΔH° for the following reaction: P4O10(s) + 6PCl5(g) ---> 10Cl3PO(g) P4(s) + 6Cl2(g) ---> 4PCl3(g) ΔH° = -1225.6 kJ P4(s) + 5O2(g) ---> P4O10(s) ΔH° = -2967.3 kJ PCl3(g) + Cl2(g) ---> PCl5(g) ΔH° = -84.2 kJ PCl3(g) + (1/2)O2(g) ---> Cl3PO(g) ΔH° = -285.7 k please explain well i do not understand these kind of problems
PART A. Use standard enthalpies of formation to calculate ΔH∘rxn for the following reaction: C2H5OH(l)+3O2(g)→2CO2(g)+3H2O(g) Express your answer using four significant figures. PART B. Use standard enthalpies of formation to calculate ΔH∘rxn for the following reaction: CH4(g)+2O2(g)→CO2(g)+2H2O(g) Express your answer using three significant figures. PART C. Use standard enthalpies of formation to calculate ΔH∘rxn for the following reaction: C(s)+O2(g)→CO2(g) Express your answer using four significant figures. PART D. Use standard enthalpies of formation to calculate ΔH∘rxn for the following reaction:...
c. Calculate ΔH° for the process Co3O4(s)→3Co(s) + 2O2(g) from the following information: Co(s) + 1/2O2(g)→CoO(s) ΔH° = -237.9kJ 3CoO(s) +1/2O2(g)→Co3O4(s) ΔH° = -177.5k d. Calculate the standard molar enthalpy of formation of NO(g) from the following data: N2(g) + 2O2 →2NO2(g) ΔH° = 66.4 k. 2NO(g) + O2 →2NO2(g) ΔH° = -114.1 kJ