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i just need 103 & 105 please explain fully
15.103. Predict which solution in each pair below will have the a. 1.25 X 10 M HNO3 or 1.00 x 10 M NaOH higher pH. b. 0.345
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e) pH of 45 mM BECOH) (K6=5x10-1) is. 103 a) 9.90 = 11, 1.0x103 07 pH. COH ) 10 14t logo 10 b) 3 pH of 1.25x105 M HNO₃ CHT) -pH of 1.6mm = 14 - PRb + logo 14 Luty (16*18*9) = 14 + 8.03 It logo (1164103) = 8.59 PH of 0.60mm + 2 logo 14 - 1 pkb =l4 8.3b) pH 20mm is WOH pH Looh of Yapka + logo =- & leg (ka) - & logo įpka - logo 3.98 -filmy, (1.20x103) – 2 logo (20x103) - 2 lo

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