Question

18) A defect in a diamond appears to be 2.90 mm below the surface when viewed from directly above that surface. How far beneath the surface is the defect? The refractive index of diamond is 2.419.

19) An object 2.00 cm high is placed 11.9 cm in front of a convex mirror with radius of curvature of 8.50 cm. Where is the image formed? If the image is formed in front of the mirror, enter a positive answer and if the image is formed behind the mirror, enter a negative answer.

15) What is the wavelength of the radio waves broadcast by an FM radio station with a frequency of 90 MHz?

Answer 1

18 Apparent depth = Real depth M d 2.90 - 2.4A d=700151 mm 19 from mirror formuk, 2 2 + + 6 = 1 f R 2 not +Is -(1109) 8.so + ITA 2 2 할 8.50 Image su = 3.13cm distance The image is formed behind the morrod so q= 3013 am 3x108 45 wavelength ujot qox,ob = 3.33 m