Question

-1 A 10 g marble rolls to the left with a velocity of 0.4 m.s and makes a head-on collision with a 30 g marble rolling to the right with a velocity of 0.2 m.s The final velocity of the larger (30 g) marble after the collision is 0.15 ms to the right. 0.200 m/s 0.400 m/s 30.0 g 10.0 g m.s A. What is the final velocity of the small marble? B. What type of collision is this?

Answer 1

Ans. 0 0.2oom/s o acom/s B @ log U = -0.4 comps he 20.0g ( Mass of A marble is marble is m, = 30g = oxing Mass of a marble is maa rog eloxio sig Initial relenty of A is .. u = 0.200m/s Initial velocity of B is Final velocity of A marble is a 0.15 m/s Led, final velocity of B marble is V2. know, every collision follow the conservation of linear momenteem. : Initial momentum a Final momentem me & Male = my+m2e2 (Boxio 10?x 0.200) + (10x1o? X – 0.40) - 70x16x0.15) + mom (1oxioſk va) 2) soxiora - → V2 = 0:25 m/s & The final velocity of small marble will be 0.25 mls to the left. -3 25 XIO B Here Initial Kinetic energy Ri smurt 2 Mq Ua bx 80x173(0-20) #bx10x163(-0-4mm) n - Vi = 6x109+ + 8x109 = 1•4x103J

Final kinetic energy is Kf = bm, at 2 mare 2 >K4 = 5x30x10*x[o.s0) 7tx 10X16XX(-0.25)? = 3.376 X104 +3•125 X169 qa 0.6581039 change of kinetic energy AK 2 kq-ké = (0.65x173)-(404x163) 2) AK = -705x109 J As, hare kinetic energy loss, so this collision is in-elastic collision.