Question

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A positive charge of size Q = 4.5 x 10-8 C creates an electric field in the empty space around it. At what distance from the charge would the electric field have a strength of 6.0 x 103 N/C? 0.068 m O 2.4 x 10-13 m 6.5 x 10-17 m 2.4 x 106 m

Answer 1

Strength of the electric field at a distance R from a charge Q is given by E kQ R2 R2 = kan R2 (9x10°)x(4.5x10-8) 6x103 R2 0.068m R= V0.068 R= 0.261m

When an object at temperature T is placed in a surrounding having temperature TO Then Heat transfered per second is given by P= = 6eA(74 -14) Here o = 5.67 x 10-8 W/m².K4 is the stefan's constant A = 0.1 m2 is the exposed area of the object T and To is the absolute temperature of object and surrounding in kelvin respectively and e = 0.2 is the emissivity So Q = (3.67 x 10-8)x( X (0.2) (0.1) * {(5 + 273)4 - (200 + 273,4} - - 49.989 g = - 49.989 J/S 1