Question

Protons move clockwise around a circular path of radius 27 cm in a magnetic field of magnitude B = 0.25 T. Proton has a charge 1.6 x 10^-19 C. What is the magnitude of the momentum of the protons and which direction is the magnetic field pointing? 1.1 x 10^-20 kg-m/s, into the plane of the circle 1.1 x 10^-20 kg-m/s, out of the plane of the circle O 0.54 x 10^-20 kg-m/s, out of the plane of the circle none of these 0.54 x 10^-20 kg-m/s, into the plane of the circle

Answer 1

B A o The centripetal cércular motion force required for this is of proton circle o DF muz given by magnetic force 'acting protons, centripetal force acts towards the centre of the = muz centripetal force magnetic force 12 (EXE') q= charge of proton velocity of proton field ga radius of arcular doop mass of proton Dimection of Force (magnetic) a direction of( T5) 8 B. mognette

çl Direction of (Ex B) is given by Right hand frule. [Index) If a point out my finger along and middle finger along then my thumb will point towards For magnet force) At any point of circle A csople 42 próton is movie moving clockwise then Bo? will point downward and to will point toward centre sto provide the nequined centripetale force Then accore hand rule B ding have to point towards out of the - page of paper. Using Izlü x) to night miz r q e 8 sind moz r o = between ū and a angle muz r -80B mie gree momentum of proton zmo = plsay)

p = sqB = 27cm X 1.6X/0! ¢ x 0.25T = 27876?m X.7.6 x 76 77 'C x 0-257 10.0 X 6.21 kgm/s 100 xjo m/s LuLX%"? 20 Kg 20 E Kg m/s Toc - out of page. of paper of 87 plone of circle
Summary: The required centripetal force to move proton in a circular Path is given by the magnetic force on proton due to magnetic field.