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A marble rolls around with no friction in a circular loop that has a radius of...

A marble rolls around with no friction in a circular loop that has a radius of 40 cm. At the bottom of the loop, the speed is 7 m/s.

A. Calculate the marble's centripetal acceleration and the angular speed when the marble is at the bottom of the loop.

B. Using conservation of energy, determine the speed of the marble at the top of the loop.

C. Calculate the magnitude of the centripetal acceleration and the angular speed of the marble at the top of the loop.

D. What was the angular acceleration of the marble as it moved from the bottom of the loop to the top? Just stated the torque that was responsible for the angular acceleration while doing this?

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Answer #1

18=40cm V=7 mis A a centripetal vi² ४ 6712 yoxo -2 0:40 7 = 17.500/ 122-5 m/s² ř ot 0:40 B 2 = 0 80 h = Ilmu? 1 m Vzt mgh 2 ,

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