Question

show all the work please


3. Solve problems (a) and (b) below. (a) In an Olympics event, a gymnast with mass 45.0 kg is jumping on a trampoline, which can be treated as a vertical spring with an effective spring constant k. You observe that she reaches a maximum height of 4.20 m above the unstretched trampoline. The trampoline will break if it undergoes the equivalent compression distance of more than d = 1.70 m. (i) From this, find the minimum safe value for k. (ii) Assuming the value of k from (i), find out how fast she is going whenever the trampoline is stretched only halfway to 1.70 m. 要回法要毫到国龙 I

Answer 1

m= 45 kg. Trampoline d 1 = = 1.70m. Cunstreched) (stretched) in streching the Restored the spring energy E Į kx² Į kd² IK (1.70) 2 This Spring energy energy will change into the finetic E = I m Vrana 2 tk 1 K (1.7002 YmVaran want to be como This man will work as a initial velocity of masse V = 0 u= max manimum height = 4.20 w?_u² s g

Uman 25 Vma 25g 2x 4.20 xlo Vman 84.00 from equation ® Varana = k (1.70)2 45 84.00 x 45 (1070) K: 1307.2 (Answer of i) Now from the all three formulae. 2 [{xels fans Imman 2 Vonan = 298 Now in and part, x= 1.70 S = ? 1 kx² I meags 1. 3079 45x lo - 1.45 ml K S : mg manimum distaned. S: 1:45 pleeprote