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show all the work please
5. Solve problems (a) to (c) below. (a) A 60.0-kg block is attached to a massless spring with force constant k = 575 N/m. (1)
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Answer #1

(a)

(i) Mass attached to the spring = m = 60 kg.

Spring constant = k = 575 N / m.

Hence, angular frequency of oscillation = \omega = \sqrt{} ( k / m ) = \sqrt{} ( 575 / 60 ) rad / s = 3.1 rad / s.

Hence, frequency of the oscillation = f = \omega / 2\pi = ( 3.1 / ( 2 x 3.14 ) ) Hertz = 0.5 Hz.

(ii) Amplitude of the motion is A = 0.35 m.

Hence, the maximum speed of the block is v = A\omega = 0.35 m x 3.1 rad / s = 1.085 m / s.

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