Question

4. Solve problems () to (e) below. (a) The wave function for a traveling wave along the x axis on a ta string is in Si units) Wx.1-0.300 sin(4x + 1x). From this find this wave's speed v. m) wavelength (1) angular frequency e, and (iv) amplitude 4. (b) The power output of a certain public-address speaker is 6.90 W. Suppose it broadcasts equally in all directions. At what distance from the speaker would the sound have an intensity of Wm..the threshold of pain for the car? (c) At what distance from the speaker would the sound be barely audible? (c) A nylon guitar string has a linear density of 9.50 g/m and is under a tension of 190 N. The ends are fixed, a distance L - 90.0 cm apart. An oscillator is inducing standing wave patterns in this string. Find the required oscillator frequency that produces five antinodes Apr. P. and. .....)

Answer 1

Salution (9) y(mit) = 0.300 Sin (47121711717) (speed vi 41n + uint = Cestent {phase alery Cosmond) Then 411dw #'llidt=0 da = 4 L have dength Stondered equaedtem ylnit A sin (wt+kin) then compare with Stendered expratin K= 41 EX = 48 d [h= 0.5m 11? Anaglar frequency 1 woll TT 10 Amplitude A=0.300 Scanned by TapScanner

С T- Igon 1600 il= 9.503/m2 9.50x103 kg/h u= 190x100 goso V- 141. 42 Scanned by TapScanner

Antinade ON nade L= adtd 2 L= 51 22 - ilor = o.g+2 5 얗 2 5 - 0-36 v=fd 41.42= fx 0.36. 141:42 fa 0.36 at 392.83 Scanned by TapScanner