ZuoTi.Pro
Question

Two manned satellites approaching one another at a relative speed of 0.500 m/s intend to dock


Two manned satellites approaching one another at a relative speed of 0.500 m/s intend to dock. The first has a mass of 5.00 x 103kg, and the second a mass of 7.50 x 10kg. Assume that positive direction is directed from the second satellite towards the first satellite. 


(a) Calculate the final velocity after docking, in the frame of reference in which the first satellite was originally at rest. m/s 

(b) What is the loss of kinetic energy in this inelastic collision? 

(c) Repeat both parts, in the frame of reference in which the second satellite was originally at rest. final velocity m/s loss of kinetic energy 3 Explain why the change in velocity is different in the two frames, whereas the change in kinetic energy is the same in both (Do this on paper. Your instructor may ask you to turn in this work.)

science   physics   
1 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

✔ Recommended Answer
Answer #1


0 0
Add a comment
Know the answer?
Add Answer to:
Two manned satellites approaching one another at a relative speed of 0.500 m/s intend to dock
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Similar Homework Help Questions

  • Two manned satellites approaching one another, at a relative speed of 0.500 m/s, intending to dock....

    Two manned satellites approaching one another, at a relative speed of 0.500 m/s, intending to dock. The first has a mass of 5.00 ✕ 103 kg, and the second a mass of 7.50 ✕ 103 kg. (a) Calculate the final velocity (after docking) in m/s by using the frame of reference in which the first satellite was originally at rest. (Assume the second satellite moves in the positive direction. Include the sign of the value in your answer.) (b) What...

  • Two manned satellites approaching one another, at a relative speed of 0.150 m/s, intending to dock....

    Two manned satellites approaching one another, at a relative speed of 0.150 m/s, intending to dock. The first has a mass of 3.50 x 10^3 kg, and the second a mass of 7.50 x 10^3 kg. (a) Calculate the final velocity (after docking) in m/s by using the frame of reference in which the first satellite was orginally at rest. (Assume the second satellite moves in the positive direction. Include the sign of the value in your answer.) (b) What...

  • Two manned satellites approaching one another at a relative speed of 0.550 m/s intend to dock....

    Two manned satellites approaching one another at a relative speed of 0.550 m/s intend to dock. The first has a mass of 4.00 ✕ 103 kg, and the second a mass of 7.50 ✕ 103 kg. If the two satellites collide elastically rather than dock, what is their final relative velocity? Adopt the reference frame in which the second satellite is initially at rest and assume that the positive direction is directed from the second satellite towards the first satellite....

  • Two manned satellites approach one another at a relative speed of 0.100 m/s, intending to dock....

    Two manned satellites approach one another at a relative speed of 0.100 m/s, intending to dock. The first has a mass of 5.00 ✕ 103 kg, and the second a mass of 7.50 ✕ 103 kg. If the two satellites collide elastically rather than dock, what is their final relative velocity in meters per second? (Adopt the reference frame in which the second satellite is initially at rest and assume that the positive direction is directed from the second satellite...

  • Two manned satellites approach one another at a relative speed of 0.210 m/s

    8.29T Elastic Collisions in One Dimension Two manned satellites approach one another at a relative speed of 0.210 m/s, intending to dock. The first has a mass of 3.24x103 kg, and the second a mass of 6.72x103 kg. If the two satellites collide elastically rather than dock, what is their final relative velocity? Assume that the collision is in 1-dimension.  

  • Two manned satellites approach one another at a relative speed of 0.230 m/s

     8.29T - Elastic Collisions in One Dimension Two manned satellites approach one another at a relative speed of 0.230 m/s, intending to dock. The first has a mass of 4.00 x103 kg, and the second a mass of 7.84x103 kg. If the two satellites collide elastically rather than dock, what is their final relative velocity? Assume that the collision is in 1- dimension. 

  • Two manned satellites approach one another at a relative velocity of v = 0.250 m/s

    Two manned satellites approach one another at a relative velocity of v = 0.250 m/s, intending to dock. The first has a mass of mı = 4.00 x 10² kg and the second a mass of m2 = 7.50 x 10 kg. If the two satellites collide elastically rather than dock, what is their final relative velocity? final relative velocity: _______ m/s 

  • Two manned satellites approach one another at a relative velocity of v = 0.250 m/s, intending...

    Two manned satellites approach one another at a relative velocity of v = 0.250 m/s, intending to dock. The first has a mass of m 1 = 4.00 × 10 3 kg and the second a mass of m 2 = 7.50 × 10 3 kg. If the two satellites collide elastically rather than dock, what is their final relative velocity? Two satellites approach each other along the same horizontal line. final relative velocity: m / s Question Credit: OpenStax...

  • What is the change in Kinetic Energy, in joules, in this frame of reference? Please can...

    What is the change in Kinetic Energy, in joules, in this frame of reference? Please can someone show me every step? Thanks (6%) Problem 15: Two manned satellites are approaching one another at a relative speed of 0.225 m/s, intending to dock. The first has a mass of 3.75 x 103 kg, and the second a mass of 9.8 x 103 kg.

  • An atom of beryllium (m 8.00 u) splits into two atoms of helium (m-4.00 u) with...

    An atom of beryllium (m 8.00 u) splits into two atoms of helium (m-4.00 u) with the release of 92.2 keV of energy. Suppose the beryllium atom moves in the positive x direction and has kinetic energy 59.9 keV. One helium atom is found to move at an angle of 31° with respect to the x axis. Find the direction of motion of the second helium atom and find the velocity of each helium atom Work this problem in the...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT