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A copper wire makes up a 139 turns, 5.60 cm diameter coil. The resistance of the...

A copper wire makes up a 139 turns, 5.60 cm diameter coil. The resistance of the coil is 3.40 Ω. There is a magnetic field parallel to the axis of the coil. If the induced current in the coil is 2.20 A, what is the rate of change of the magnetic field?

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Answer #1

d = 5.60m N=1391 Rr. 3.402 { induced = 2.20 A 0=NB.A dd =NA - dB dt H dd at E -AdBxN 11 alle E R LI R de dB 도 IR A - 2.208 3.

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