A 30.0 cm diameter coil consists of 37 turns of cylindrical copper wire 2.40 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 9.50 x 10-3 T/s. Determine the current in the loop in milli-amps (the resistivity for copper is 1.72 x 10-8 Ω.m).
Find the length of the wire and use that to find the resistance.
Use Faraday’s law of electromagnetic induction to find the EMF
induced and then use Ohm’s law to find the current as shown
below
A 30.0 cm diameter coil consists of 37 turns of cylindrical copper wire 2.40 mm in...
A 29.0 cm diameter coil consists of 23 turns of cylindrical copper wire 2.00 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 7 x 10^-3 T/s. Determine the current in the loop in milli-amps (the resistivity for copper is 1.72 x 10^-8 Ω.m).
A 22.0-cm-diameter coil consists of 30 turns of circular copper wire 2.8 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 9.35×10−3 T/s . The resistivity of copper is 1.68×10−8Ω⋅m. Determine the current in the loop. Determine the rate at which thermal energy is produced.
A 24.0-cm diameter coil consists of 45 turns of circular copper wire 3.0 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 7.85×10−3 T/s . The resistivity of copper is 1.68×10−8Ω⋅m. Determine the current in the loop. (Express your answer to two significant figures and include the appropriate units.) Determine the rate at which thermal energy is produced. (Express your answer to two significant figures and include the appropriate units.)
A 24.0-cm diameter coil consists of 45 turns of circular copper wire 3.0 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 7.85×10−3 T/s .The resistivity of copper is 1.68×10−8Ω⋅m. a) Determine the current in the loop. (Express your answer to two significant figures and include the appropriate units.) b) Determine the rate at which thermal energy is produced.(Express your answer to two significant figures and include the appropriate units)
A 20.8 cm -diameter coil consists of 30 turns of circular copper wire 2.4 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 7.64×10−3 T/s . PART A: Determine the current in the loop. PART B: Determine the rate at which thermal energy is produced.
A 22.0-cm-diameter coil consists of 28 turns of circular copper wire 2.6 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 8.65 * 10 -3 T / s . Determine: the rate at which thermal energy is produced ans: _ W
#16
A 22.0-cm-diameter coil consists of 28 turns of circular copper wire 2.6 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 8.65 Times 10^-3 T/s. Determine the current in the loop, and the rate at which thermal energy is produced. A power line carrying a sinusoidally varying current with frequency f = 60 Hz and peak value I_0 = 55 kA runs at a height of 7.0 m across...
A 25 cm diameter tangent galvanometer consists of 15 turns of 0.5 mm diameter copper wire and has a current of 2 A running through it. Calculate the total internal resistance of the wire and the magnetic field at the center of the loop. (The resistivity of copper is p = 1.69 x 10-8 ohm meter).
Constants copper wire 2.2 mm in diameter. A uniform Periodic Table Part A A 23.4 cm -diameter coil consists of 30 turns of circular Determine the current in the loop. magnetic field, perpendicular to the plane of the colil, changes at a rate of 7.16x10-3 T/s Express your answer using two significant figures. Symbola Ledo redo resat keyboard shortcuts helo Submit Request Answer Part B Determine the rate at which thermal energy is produced Express your answer using two significant...
A 100.0-m-long, 1.20-mm-diameter copper wire (resistivity 1.70*1082m) is shaped into a circular coil that consists of 150 identical turns. The coil is then connected to the terminals of a 9.00-V-battery that has internal resistance of 1.50 12. Calculate the strength of the magnetic field (due to the current running through the coil) at the center of the coil.