Question

Two long, parallel wires are attracted to each other by a force per unit length of 350 N/m. One wire carries a current of 16.0 A to the right and is located along the line y = 0.470 m. The second wire lies along the x axis. Determine the value of y for the line in the plane of the two wires along which the total magnetic field is zero. m Additional Materials eBook

Answer 1

Magnetic field produced by Y wire a current carrying is given by 16A (wire 1) B Mol 2tr 0.470m →Y (wire 2) Here Mo = Perme ability of free space TH/A 4Axlo7 I Current r distance wire carrying B = 6.8 x 10 T 2T on a Thus Magnetic field produced by wire Current of 16A at the position of other wire will be (4R X10 TMA) (16 A) -6 (0.470m) Magnetic force exerted Current placed in a magnetic field is given by i B l i = § () Here is current, B=magnetic field, l=length We have 350 Nm , wire carrying E = iB x156T B = 6.8 X10 l Current in the second wire will be F B l 618x1067 i-B (350x16 Nim) i = 51.47 A

these two wires net magnetic will be are At any point between field will zero s If magnetic fields created by these two wires equal in magnitude and opposite in direction. Then, magnetic field created by wire 1= Magnetic field created by wire 2 to I (0.470 70m-y) 0 Mo 2n y 2Ã Oru rom- y I i 9 16A 0.urom Ч - 1 51.47 A 0.470 m 1 + 16A Sl.u7A 9 -> = 0+36 m Ourom y 1:31