Question

2. During a remote class session, a student listens to a wise and witty Physics Instructor through his laptop. Standing a distance of 3.575m from the laptop speaker, decibel level of the instructor's voice is 103.0dB, as heard by the student. Don't judge me. This is how ! dress for class. laptop d social isolation gives you more time to study!! i. Determine the sound intensity of the instructor's voice as heard by the student. I'm So socially distant... ii. Calculate output power of the laptop speaker as the instructor is talking.

Answer 1

heard 103 dB (a Sound 103 = to log ( 1 ) 10.3-12 lo I = -1•7 10 I = W/m² - 0-199 Intensity heard (Intensity lü output power heard) x4 a 4² 0.199 847 (3.5753) P P= 3.2 045 W

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