Question

Two long parallel wires carry currents of 2.07 A and 6.87 A . The magnitude of the force per unit length acting on each wire is 4.77×10−5 N/m . Find the separation distance ? of the wires expressed in millimeters.

____mm

Answer 1

Force per unit length of wire

F=$\mu _{0}$
11
$I_{2}$/(2$\pi$d)

$\mu _{0}$=4$\pi$x$10^{-7}$

=current in first wire=2.07A

11

$I_{2}$=current in second wire=6.87A

d=distance between them=?

F=4.77X$10^{-5}$N/m

F=$\mu _{0}$
11
$I_{2}$/(2$\pi$d)

d=$\mu _{0}$
11
$I_{2}$/(2$\pi$F)=4$\pi$x$10^{-7}$X2.07X6.87/(2$\pi$X4.77X$10^{-5}$)=5.96cm=59.6mm