Two long parallel wires carry currents of 3.19 A and 7.87 A. The magnitude of the force per unit length acting on each wire is 4.49 × 10-5 N/m. Find the separation distance of the wires expressed in millimeters.
F = mu0 * i1 * i2 * L / 2 pi d
d = mu0 * i1 * i2/ [ 2 pi * (F/L) ]
= (4pi * 10-7 * 3.19 * 7.87 ) / [ 2 pi * 4.49 * 10-5 ]
d = 0.112 m = 112 mm
Two long parallel wires carry currents of 3.19 A and 7.87 A. The magnitude of the...
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