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(1 point) In an RLC series circuit, the source has a potential difference of 130 V...
(1 point) In an RLC series circuit, the source has a potential difference of 160 V...
(1 point) In an RLC series circuit, the source has a potential difference of 160 V (rms). The impedance is 165 12 and the resistance is 44 22. Find: a) the average power delivered by the source; W P= b) the power factor;
In an RLC series circuit, the source has a potential difference of 160 V (rms). The...
In an RLC series circuit, the source has a potential difference of 160 V (rms). The impedance is 175 Ω and the resistance is 40 Ω . Find: a) the average power delivered by the source; P = W b) the power factor;
In an RLC series circuit, the source has a peak potential difference of 150V, and a...
In an RLC series circuit, the source has a peak potential
difference of 150V, and a frequency of 65?Hz. Take ?=15Ω, ?=180?F,
?=0.1H.
c) the average power delivered by the source; W
d) the power factor.
(1 point) In an RLC series circuit, the source has a peak potential difference of 150 V, and a frequency of 95 Hz. Take R = 1512, C = 180 uF, L = 0.1 H. Find: a) XL and Xc; XL = 13 12...
(1 point) In an RLC series circuit, the source has a peak potential difference of 150...
(1 point) In an RLC series circuit, the source has a peak potential difference of 150 V, and a frequency of 70 Hz. Take R = 2012, C = 260 pF, L = 0.1 H. Find: a) XL and Xc; XL = 12 Xc = 12 b) the phase angle; degrees c) the average power delivered by the source; W d) the power factor.
(1 point) In an RLC series circuit, the source has a peak potential difference of 120...
(1 point) In an RLC series circuit, the source has a peak potential difference of 120 V, and a frequency of 55 Hz. Take R=1212, C = 170 uF, L = 0.3 H. Find: a) X and Xc; XL XC = 12 = 12 b) the phase angle; degrees c) the average power delivered by the source; W d) the power factor.
(1 point) In an RLC series circuit, the rms potential difference provided by the source is...
(1 point) In an RLC series circuit, the rms potential difference provided by the source is V = 150 V, and the frequency is f 240 Hz. Given that L = 0.1 H, C = 40 uF, and VR = 20 V, find: T a) I (rms); I A b) R; R 12 c) VL (rms); VL: V d) Vc (rms). Vc = V
(1 point) In an RLC series circuit, the rms potential difference provided by the source is...
(1 point) In an RLC series circuit, the rms potential difference provided by the source is V = 190 V, and the frequency is f = -0 Hz. Given that L = 0.6 H, C = 75 uF, and VR = 20 V, find: a) I (rms); I = b) R; R= c) VL (rms); VL = d) Vc (rms). Vc =
(1 point) In an RLC series circuit, the rms potential difference provided by the source is...
(1 point) In an RLC series circuit, the rms potential difference provided by the source is V = 220 V, and the frequency is f = Hz. Given that L 0.35H, C = 45 pF, and VR = 75 V. find: 260 2 a) I (rms); A b) R; R 22 c) VL (rms); VL V d) Vc (rms). Vc V
(1 point) In an RLC series circuit, the rms potential difference provided by the source is...
(1 point) In an RLC series circuit, the rms potential difference provided by the source is V f = 260 Hz. Given that L -0.35 H, C = 454F, and Vr = 75 V.find: 220 V, and the frequency is a) I (rms) I = 0.6452 A b) R R 116.2 12 c) VL (rms); VL 116.48 V d) Vc (rms). 27.35 Vc V
(0 points) In an RLC series circuit, the rms potential difference provided by the source is...
(0 points) In an RLC series circuit, the rms potential difference provided by the source is V = 200 V, and the frequency is f 290 Hz. Given that L = 0.25 H, C = 60 uF, and VR = 65 V, find: = 7T a) I (rms); I = A b) R; R= 12 c) VL (rms); Vi V d) Vc (rms). Vc = V
(1 point) In an RLC series circuit, the source has a potential difference of 160 V (rms). The impedance is 165 12 and the resistance is 44 22. Find: a) the average power delivered by the source; W P= b) the power factor;
In an RLC series circuit, the source has a peak potential
difference of 150V, and a frequency of 65?Hz. Take ?=15Ω, ?=180?F,
?=0.1H.
c) the average power delivered by the source; W
d) the power factor.
(1 point) In an RLC series circuit, the source has a peak potential difference of 150 V, and a frequency of 95 Hz. Take R = 1512, C = 180 uF, L = 0.1 H. Find: a) XL and Xc; XL = 13 12...
(1 point) In an RLC series circuit, the source has a peak potential difference of 150 V, and a frequency of 70 Hz. Take R = 2012, C = 260 pF, L = 0.1 H. Find: a) XL and Xc; XL = 12 Xc = 12 b) the phase angle; degrees c) the average power delivered by the source; W d) the power factor.
(1 point) In an RLC series circuit, the source has a peak potential difference of 120 V, and a frequency of 55 Hz. Take R=1212, C = 170 uF, L = 0.3 H. Find: a) X and Xc; XL XC = 12 = 12 b) the phase angle; degrees c) the average power delivered by the source; W d) the power factor.
(1 point) In an RLC series circuit, the rms potential difference provided by the source is V = 150 V, and the frequency is f 240 Hz. Given that L = 0.1 H, C = 40 uF, and VR = 20 V, find: T a) I (rms); I A b) R; R 12 c) VL (rms); VL: V d) Vc (rms). Vc = V
(1 point) In an RLC series circuit, the rms potential difference provided by the source is V = 190 V, and the frequency is f = -0 Hz. Given that L = 0.6 H, C = 75 uF, and VR = 20 V, find: a) I (rms); I = b) R; R= c) VL (rms); VL = d) Vc (rms). Vc =
(1 point) In an RLC series circuit, the rms potential difference provided by the source is V = 220 V, and the frequency is f = Hz. Given that L 0.35H, C = 45 pF, and VR = 75 V. find: 260 2 a) I (rms); A b) R; R 22 c) VL (rms); VL V d) Vc (rms). Vc V
(1 point) In an RLC series circuit, the rms potential difference provided by the source is V f = 260 Hz. Given that L -0.35 H, C = 454F, and Vr = 75 V.find: 220 V, and the frequency is a) I (rms) I = 0.6452 A b) R R 116.2 12 c) VL (rms); VL 116.48 V d) Vc (rms). 27.35 Vc V
(0 points) In an RLC series circuit, the rms potential difference provided by the source is V = 200 V, and the frequency is f 290 Hz. Given that L = 0.25 H, C = 60 uF, and VR = 65 V, find: = 7T a) I (rms); I = A b) R; R= 12 c) VL (rms); Vi V d) Vc (rms). Vc = V
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