In an RLC series circuit, the source has a potential difference of 160 V (rms). The impedance is 175 Ω and the resistance is 40 Ω . Find:
a) the average power delivered by the source; P = W
b) the power factor;
1) power delivered by the source :
P = (Vrms) ^2*Pf/Z
P = 160*160*0.228/175
P = 33.35 Watt
2) power factor :
Pf = R/Z
Pf = 40/175
Pf = 0.228
In an RLC series circuit, the source has a potential difference of 160 V (rms). The...
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