Question

(х 0.200 m 1. Four long parallel conductors carrying equal currents of 1 = 5.00 A are located at the edges of a square with edge length 0.200 m. If needed, you may assume that each conductor has a length of 2.00 m. The direction of the current is into the page at point A, and out of the page at B, C, and D. a. Calculate the magnetic field at point P. {5 Points) B D 0.200 m

Answer 1

Solutions CA current in each wire I = 5:00 A 0.200 m edge length of square =0.200m B 0-200 m Now any the distance of point p from conductor 8 = [110.200)+10.2002 = 0-200 JZ 1/2 2 r=ool ſ2 m x= 0.1414 m BE BAT C) ४ 27 Mo. (a) the magnitude of magnetic field at point Pi Mo Dulu on top B=6 Mo I La BE 2) = 2x (2x10-7) = 141.44 x 10-7 7 28 27 ) 5 х 0.1414 14.14 M T Lit Hence, the magnitude of magnetic field Am will be 14.14 MT

magnetic field at con 45 Во Beli By = BBS n45° - BA riog (b) the corner C- B = VBZ + 8? BB Horizontal component- By E-Bo-Bp Cos 45' YBA --- in cos 45° ) Cos 45')'sib hobia 5-(2x102 ) - (2010?a ) EL-5x10-6 3:536x10-6)T Bx = – 8,536x10167] Vertical component- -13.536x10-6 5x10-6) [ By 1.464 x10-6 TL So net magnetic field- B =[V(8.536)2+(-1.464)2 ] x10-6 B = 8.66X106 - 1 B = 8.66 MT Hence, the magnetic field at Am corner c will be 8.66 MT, Bocor