Question

Four long, parallel conductors carry equal currents of I = 4.21 A. The figure shown below is an end view of the conductors. The direction of the current is into the page at points A and B (indicated by the crosses) and out of the page at C and D indicated by the dots). Calculate the magnitude and direction of the magnetic field at point P, located at the center of the square with edge of length 0.200 m. 5.95 magnitude Your response differs from the correct answer by more than 10%. Double check your calculations. ut direction downward A X -------- . C i 0.200 m B * ------- 0.200 m D

Answer 1

Magnetic field due to long current carrying conductor is given by :

, here I= current , r = distance from the wire

Ко/ В = 2ar

so, magnetic field for each wire will be same since I and r are equal ,

B1 = B2 = B3 = B4 = B== Ho X 4.1 27 x (0.141) 111 = 5.81 x 10-87

as shown in the figure,

2Bsin 45 I 2Bsinus asias 28 K 05195 2B 2X 2 Blos45°

magnetic field in horizontal direction will cancel out and net magnetic field will remain in downward direction

  

Bnet = 4B cos 45 = 16.43 x 10-8T = 0.1644T

Direction will be downwards .