Question

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Four long, parallel conductors carry equal currents of I = 6.70 A. The figure below is an end view of the conductors. The current direction is into the page at points A and B and out of the page at C and D. AX • С 1 B (a) Calculate the magnitude of the magnetic field at point P, located at the center of the square of edge length = 0.200 m. (b) Determine the direction of the magnetic field at point P, located at the center of the square of edge length l = 0.200 m. Part 1 of 6 - Conceptualize For a field in the millitesla range, we would need a coil with many turns. Here we expect a field on the order of several microteslas. The field lies in the plane of the page since the currents flow into and out of the page. The total magnetic field will not be directed to the right or to the left. Part 2 of 6 - Categorize We will find the magnetic field vector created at point P by each wire. Then we will perform a vector addition of the four fields. Part 3 of 6 - Analyze Each wire is distant from P by a = 1+1/2 = V/2. Each wire produces a field at P of equal magnitude given by the following. Ho! BE

Answer 1

I= 6.70A The magnitude dure to each current will be uso Be BB same B= Ho IT a R e 0.2 T2 - ) + २ 6.70 -7 x 2x = 9.47 HT Ho => B E) B= 2x10 0.2 Since BABB = Bet Be Ben Bor BAN Box the horizontal components cancels but YBDY a Bay & Bey only wertical components give not field & Boy BN = 4x B x Cosus. ux flo 51 20 UI BN = fo PTT 2x107 x 4 x 6.7 l But = 2688 107 T 0 B. 26.8 HT Net dign will i downside y diring :7 yoxlo Hol x 6.7 # B= B= gra = 9.47 MT 211 x 10.141