For the circult given on the right, calculate the power dissipated in the 42 resistor. 2.00...

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Question

Answer 1

Answer #1

Tov 32 12 12 4. SV loop! 10- 2i, tiz -5 +42-3%, = 0 59,- 512=5&i, -i2=1 - 0 loop 2 5-12-10 li, tiz)-42 = 0 10i, + 1512=5211 +

Answer 2

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