Question

Calculate the power delivered to each resistor in the circult shown in the figure below. (Let R - 5.00 0, R2 = 2.000, and V - 21.0 V.) R} 1.000 w 4.00 2 resistor R, 4.00-ohm resistor resistor R 1.00-ohm resistor Need Help? Read Watch

Answer 1

First, find the equivalent resistance

Consider the circuit

Resistors are connected in parallel

R2 and 12

十。 - -

212 | +- 112 1-1 +

-

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Resistors, are connected in series

R1, R, and 422

Reg = R1 + R, +42

Req = 52 + 2 + 492

5*3 2 4*3 Reg = 1+3+3+ 1*3

15 2 Req=5+3+ 12 15+2 + 12

29 Req = 32

Reg = 9.666722

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Total current,

V Reg 211 9.66672

I = 2.17244

Consider resistor, $R_{eq}$

Resistors, are connected in series

R1, R, and 422

In Series connections, current across all devices is the same.

11 = 1, = 14n = 1 = 2.1724A

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Voltage,

V= I * R = 2.1724A * نا | نت

V = 1.4483V

Consider resistor $R_{p}$

Resistors are connected in parallel

R2 and 12

In Parallel connections, voltage across all devices is the same.

V = Vin = V2 = 1.4483V

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Power in resistor R₁,

P1 = 1; * R1 = (2.1724A) * 522

ANSWER:
Pi = 23.5966W

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Power in $4\Omega$ resistor,

P4n = 1 * R4n = (2.1724.A)* 492

ANSWER:
Рn = 18.877ЗИ

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Power in resistor R₂,

(1.448352 20 B

ANSWER:
P = 1.0488W

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Power in $1\Omega$ resistor, $P_{1\Omega }=\frac{V_{1\Omega }^{2}}{R_{1\Omega }}=\frac{(1.4483V)^{2}}{1\Omega }$

ANSWER:
Pin = 2.0976W

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