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OT, LTIC 2.7 12 U2 = myvi + m2v2 where u and vrefer to initial and final velocities. 10 pts Question 12 A 0.523-kg mass suspe

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Answer #1

T = 2 pi sqrt(m/k)

1.02 = 2 pi sqrt(0.523/k)

k = 19.85 N/m

3.07 = 2 pi sqrt(m'/19.85)

m' = 4.74 kg

Added mass, dm = 4.74 - 0.523 = 4.22 kg

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