A proton is accelerated by a electric potential of 50 kV. This proton is heading towards...

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A proton is accelerated by a electric potential of 50 kV. This proton is heading towards a constant magnetic field of 1.2 T p

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Answer 1

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V=50kV B = 1.2 T NIB Im = q (VX B) = qUB UB= mv2 r qUBE qB=mo r r= um qB / - авт) 0 e proton- ft mu?=ė V 2 ev Envegy conserva Т- 2TY 2px 2T 9 ) AB - 2 m) Ир LR Т: г 2 x 3:1 и 1-6 Эх10 - 22 - 6 х/0 19x 12 Т- (о. Ч% 76х10 1. 92 Хее -8 Т= S.Чех (0 °C

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