A proton accelerated through a potential of 12.0 kV enters a device which has both an electric and a magnetic field, that are perpendicular to each other as shown in the figure. This device is known as a "velocity filter", because only protons with a given velocity are not deflected and continue their trajectory along the y-axis through the aperture shown in the figure.
Indicate the directions of both the electric force and the
magnetic force.
+x -x +y -y +z -z Direction of the Electric Force
+x -x +y -y +z -z Direction of the Magnetic Force
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The E-field between the parallel plates has a magnitude of 6.000×105 N/C. Calculate the magnitude of the electric force on the proton.
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Calc
ulate the magnitude of the
B-field so that the net force on the proton due to both the
electric and magnetic fields is zero.
Homework Answers
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A proton accelerated through a potential of 12.0 kV enters a
device which has both an...
A proton, that is accelerated from rest through a potential of 13.0 kV enters the velocity...
A proton, that is accelerated from rest through a potential of
13.0 kV enters the velocity filter, consisting of a parallel-plate
capacitor and a magnetic field, shown below.
The E-field between the parallel capacitor plates is
3.9·105 N/C. What B-field is required so that the
protons are not deflected? (Ignore relativistic effects for high
velocities.)
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A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative x direction and has a magnitude of 2.52 mT. At one instant the velocity of the proton is in the positive y direction and has a magnitude of 1960 m/s. At that instant, what is the magnitude of the net force acting on the proton if the electric field is (a) in the positive z direction and has a magnitude of 3.44 V/m, (b)...
A proton, that is accelerated from rest through a potential of
13.0 kV enters the velocity filter, consisting of a parallel-plate
capacitor and a magnetic field, shown below.
The E-field between the parallel capacitor plates is
3.9·105 N/C. What B-field is required so that the
protons are not deflected? (Ignore relativistic effects for high
velocities.)
A proton is accelerated by a electric potential of 50 kV. This proton is heading towards a constant magnetic field of 1.2 T perpendicular to its velocity.(12 points) • Compute the speed of the proton due to the electric potential. . Once the proton is inside the magnetic field region, what is the radius of curvature of its trajectory • What is the period of revolution?
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A proton is accelerated through a 3.11 kV potential difference and directed between parallel plates separated 12.3 mm as shown below. The EMF of the battery is 10.0 V. What is the magnitude and direction of the uniform magnetic field between the plates that allows the proton to travel undeflected?
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