Question

The flywheel of an engine has moment of inertia mº about its rotation axis. 2.30 kg W

Part A What constant torque is required to bring it up to an angular speed of 400 rev/min in 8.00 s, starting from est? Expre
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Answer #1

ㄴ Given moment of inendia, I=2-30 kg Wi=o rad/s نيا f = 400 rev / min 400 X 217 60 Madis = 41.87 rad/s t=8 S- we know, know,hope it helps.

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