Question

Hibbeler 17-26: The jet aircraft has a total mass of 22 Mg and a center of mass at G. Initially at take-off the engines provide a thrust 2T = 4 kN and T' = 1.5 kN. Neglect the mass of the wheels and, due to low velocity, neglect any lift caused by the wings. a. Find the acceleration of the plane b. Find the normal forces on the nose wheel and each of the two wing wheels located at B. Your answer must include a free body diagram. Answers (your unit vectors might differ): a. åplane/e = 0.250 m êx b. ÑA = 72.6 kNey, Ng = 71.6 kNêy 27 2.5 m 2.3 m B -3 m- -1.2 m @A 6 m

Answer 1

Solinglet from Diagram b=2.5m c=2.3m d 3m C=6m F = 1.2m Partes Total mars (M) = 22 mg - Center of mass at G Geven Data 27=UKN - 4000N = 1500N T'=1.5kn Fx Mag 2T'+ T' 22x10²a 4000 + 1500 AG = 0.250 m/s2 Hence, the acceleration of the plane = 0.250 m2 Part bol Taking moment about B -27X2,3 TIX 2.5 - mgx3+RA X 9 -mag X 1.2 _.4000 x 2.3-1500X2.5–22x10349.81x3 + 9 RAS-22 x 103 x 0.250 X12

Hence RA = 72.6 KN 2 RB TRA - mg=0 22x9.81 – 72.6x103.N Re 2 11.6 KN 71.61 KN Hence Re