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A string fixed at both ends has successive resonances with wavelengths of 0.55 m for the...

A string fixed at both ends has successive resonances with wavelengths of 0.55 m for the nth harmonic and 0.53 m for the (n + 1)th harmonic.

(a) What are the following values?

nth harmonic
(n + 1)th harmonic


(b) What is the length of the string?
m

Use the fact that the resonance frequencies are multiples of the fundamental frequency and are expressible in terms of the speed of the waves and their wavelengths to find the harmonic numbers. You can find the length of the string by using the standing-wave condition for a string fixed at both ends.

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Answer #1

Kolmis a string fined at both ends @ 21 in 2h 0+1 n+1 И Giveni for hength harmonic 2 Length of string. Anna we ca can ivrite

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