Question

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Shown in the figure below is a capacitor. Each plate has an area of A = 3.54e-02 m2 and has a gap d = 5.1e-04 meters. At the first moment, the capacitor is empty. At the second moment it is partly filled with a dielectric of constant k = 3.22. The dielectric layer leaves a free area of Az = 1.416e-02 m2 and covers the filled area A2 = 2.124e-02 m2. Empty Capacitor Partly Filled Capacitor Area = A Area = A1 Area = A2 dielectric constant K d o] d Write the FORMULA for the capacitance of the empty capacitor. Determine the capacitance of the empty capacitor Cempty = Farads When you partly fill the capacitor, which of these best describes the new configuration: O Both series and parallel O Parallel O Series ONeither series nor parallel Determine the formula for the partly filled capacitor Cfilled = Determine the value of the partly filled capacitor Cfilled = Farads NOTE: Decide whether the partly filled capacitor acts like parallel or series by following the charge: • If the charge splits between the caps, parallel.

Answer 1

→ Capacitance of empty Capacitors C = Aco >C= 3.54x10² x 5.85*102 5.1 x 18+ = 6.143x15io Farad

C = A, E + A2 Eolk) d d ¿ '= (A + A₂k) Eo d. '={1416x1 2+2-724xio x3-22 -12 8,85x10 5018184 = 14,33x10 ° F
If the dielectric is placed as shown in the figure its a parallel setup