Question

One end of a cylindrical pipe has a radius R = 2.5 cm. Water (density = 1,000 kg/m) streams steadily out at v = 5.0 m/s. What
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Answer #1

Au 1 flow rate A = cross sectional area of pipe velocity of Flowe of water (782) = *( 2.5cm)? x 5 m/s (2.5X102 m x 5ms flow rSummary: volume flow rate is equal to the product of cross sectional area of pipe and velocity of water flow.

And mass flow rate is the product of volume flow rate and density of water.

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