Question

The next three questions refer to a vertical cylindrical beaker holding water. The density of water is 1.0 g/cm3. The volume of a cylinder is LaTeX: \piπR2H, where R is the radius of the cylinder and H is the height.

If the beaker holds 1.44 kg of water and the bottom of the container has a diameter of 6.0 cm, what is the weight of the water in Newton's?

If the beaker holds 2.0 kg of water and the bottom of the container has a diameter of 8.9 cm, what is the height of the water centimeters?

If the beaker holds 2.75 kg of water and the bottom of the container has a diameter of 5.69 cm, what is the water pressure at the bottom of the cylinder in Pascals (N/m2)?

Answer 1

If

Sol? S = 1 gm/cm3 water. (a) of beaker holds 1.44 kg So the weight of water. - لی mg g=10m/s wa 1,44 X 10 W=14.4 N water. (b) If beaker hold ang Riameter af baseer 0=8.9cm let height of water be the mo ha Р TRS ha 2 x20100 2x3-1448.9 x 1080 m =2rek = 0.007 m ܒܢ the preffure Ich che onem. (c) If beaker hold 2.75 kg. Diameter of bose D = 5.63 CM at the bottom bottom is fim 20RS then poesgore. ng p= f g h = fg x 2RR p 25R po 2-75 X 10 X 2 X 100 2X3.14 X 5569 P = 153.9) N/m² required pressure x m =