Question

The next three questions refer to a vertical cylindrical beaker holding water. The density of water is 1.0 g/cm³. The volume of a cylinder is πR²H, where R is the radius of the cylinder and H is the height.

If the beaker holds 1.87 kg of water and the bottom of the container has a diameter of 6.29 cm, what is the water pressure at the bottom of the cylinder in Pascals (N/m²)?

Answer 1

(A)= ar? Ad² Here, the force acting on the bottom of the eyllinder is only the gravitational force acting by water in the cyllinder, So, force exerted by water is (F) = mg where, ma 1.87kg; g=9.81miss Area of the bottom of cyllinder is [ d = diameter, p=radius. now, pressure at the bottom of the cylinderts. (P) =F/A mg nd² diameter (d) **(6-29x169) 3 G 29 cm = 60 29x102 m 5903-63 Pa{N/m2) .. the water pressure at the bottom of the cyllinder its is 5903.63 Pascals (N/m2). or, P= Amg Pa I d2 al 4.87 x 9.8 pa