Question

The element un unquadium (49. Trug) has been created by fusing calcium ions Ca) with plutonium nuclei (24 Pu). The calcium ions are doubly charged (+2e) and have a mass of 7.96 x 10-26 kg. To accelerate these ions to a high enough energy to fuse with plutonium, they are repeatedly accelerated by an electric potential difference. They are contained in a magnetic field between these accelerations. In one stage of the acceleration process, calcium ions enter the accelerating chamber at a speed of 1.00 x 10 mts and exit it at a speed of 275 x 10 m/s. They immediately enter a magnetic field and follow a path that has a radius of 1.24 m. 13. Which of the following equations could be the nuclear reaction equation for the fusion of calcium and plutonium in the production of ununquadium? A Ca + 2 Pa Vuq +ş a B. Ca +24 På → Uuq +3_9B+ c. Ca + +30 D. Ca +24 Pu +3ļa 21, Vuq 24 Pu + 114 289 Uuq +

Answer 1

4.9 244 Cat Pu 94 20 Since this this is a fusion reaction, No. of protons = 20 t 94 = 114 No. of neutrons = (48-20) + (244-94) = 28 + 150 178 This should be in product side . same so the possible reaction is :- 48 244 289 c) Cat Pu Uuq t 3 114 3'e o 20 94