Question

The element un uoquadium Uuq) has been created by fusing calcium ions Ca) with plutonium nuclei (24 Pu). The cakium ions are doubly charged (+2e) and have a mass of 7.96 x 10-2 kg. To accelerate these ions to a high enough energy to fuse with plutonium, they are repeatedly accelerated by an electric potential difference. They are contained in a magnetic field between these accelerations. In one stage of the acceleration process, calcium ions enter the accelerating chamber at a speed of 1.00 x 10 m/s and exit it at a speed of 275 x 100 m/s. They immediately enter a magnetic field and follow a path that has a radius of 1.24 m. The decay chain of nunquadium-289 is shown below. TÀUng- Uub +X+W DS+Y Unusquadium-289 bas a half-life of 30.4 s. 16. If 1.00 ug of ununquadium-289 is initially produced, the mass of ununquadium-289 remaining after 1.00 min will be A. 0.255 pg - B. 0.507 Mg C. 0.703 ug D. 0.977 ug

Answer 1

In Nz -kt NO In (0.5) -K (30.4) = -K ( 30.4) - 0693 K-0.693 -0.0228 36.4 Now for ť = 1 min Go sec -Kt' Nt Ne 0:0228 (60) Nz =1 -1.368 e le z Nt t - 0.255 ug