from figure,
F1x = 5.1*cos(35) = 4.18 N
F1y = 5.1*sin(35) = 2.92 N
F2x = 0
F2y = 5 N
Fnetx = F1x + F2x
= 4.18 + 0
= 4.18 N
Fnety = F1y + F2y
= 2.92 + 5
= 7.92 N
magnitude of net force, Fnet = sqrt(Fnetx^2 + Fnety^2)
= sqrt(4.18^2 + 7.92^2)
= 8.96 N <<<<<<---------Answer
direction : theta = tan^-1(Fnety/Fnetx)
= tan^-1(7.92/4.18)
= 62.2 degrees <<<<<<---------Answer
Pre-Lecture - PHYS1310 200/CLIN MAST Homework PHYS10 200/CLIN MAST Dacute Self Assessments 16. (-/2.5 Points) DETAILS...
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