Question

Problem 3: You and your friend are both starship captains. Your friend is orbiting a planet in a circular orbit at an altitude of 2 x 10 m above the surface. Your ship is also in a circular orbit but is at an altitude of 7 x 10ºm above the surface. (Mplanet = 2 x 1023 kg and Rplanet = 4 x 106 m) a) [4 points] What are the orbital speeds of the two ships in their circular orbits? b) [6 points] By what amount would you need to alter your xelocity to drop your Diagram for parts B&C orbit down so that it touches your friend's orbit as shown in the diagram Your to the right? Would this be an increase с Friend or decrease in velocity?

c.) How fast would you be moving at point "C" in the provided diagram?

d.) At point C, you determine that the center of the planets moon (Mmoon = 6 x 10^22) is 4 x 10^7 m away from you. What is the escape velocity for the planet/Moon system at this point?

Answer 1

A object travell in a uniform circular orbit is called orbital speed of an object.

Orbital speed is most important cimputation , in the abive question there are two man or friend who travell in orbit with a orbital speed, the calculation of their orbital speed is as follow-

planet Vo you with Just the gravitational force a circular acceleration, following must be true in the direction of the planet (and circle). Fret - mar center GMME 82 muz r The above formula could be solve for v se velocity needed for an orbit with radius S.