Question

Problem 3: You and your friend are both starship captains. Your friend is orbiting a planet in a circular orbit at an altitude of 2 x 10 m above the surface. Your ship is also in a circular orbit but is at an altitude of 7 x 10 m above the surface. (Mplanet = 2 x 1023 kB and Rplanet = 4 x 106m) a) [4 points] What are the orbital speeds of the two ships in their circular orbits? Diagram for parts B&C Your b) [6 points] By what amount would you need to alter your velocity to drop your orbit down so that it touches your friend's orbit as shown in the diagram to the right? Would this be an increase or decrease in velocity? с Friend

Answer 1

ANSWER :
o radius of friend's orbit = Rp=6x100 m. radius of my orbit = Rm = 11 X 106m Mplazet = 2x1023 kg Rplanet - 4X106m Rp and Rm are measured from the centre of the planet let me be the mass of friends ship. mf vf Geplanet me R?f Rf here. Ne » orbital speed of friend's ship. GM planet ve Rp. 6:673x10 "x2x103 -2.1092 x 103 m/s GX 106 similarly orbital speed of myship is vm GMplanet 6-673 x 10""x 2X1023 1 X 106 Rmi <1-10149 x 10 mls. b) To dropdown to friends or bit my orbital speed should change from 1-10149x 103 m/s to 2.1092x103 mls.

9 change in speed sequired Ps 1000771x10?mls It would be an increase in the velocity. at point'e the radius of curvature of the two orbits are same hence my speed atk equals friend's speed in his orbit ire 2.1092 x 103 mls. Moon Rel planet Mmoon 6x1042 kg: 4x107m. at c. relocity kinetic energy let v be the escape My at c = 1/2 move potential energy atė'. GMmoon mm Gerplanet Mom Rf. ཀ here mm mass of my ship. ath! since is the escape velocity hence total energy is zero. lie. GM planet Mm mm V² GMmoon mim Rf [2[ V= GMmoon r GMplanet ]]} + Rf

2X6 313×10 어82 21023 4 니X(01 G8106 음 ve 15 - 120145 mls ♡