Question

CAN SOMEONE ANSWER #5 & #6 PLEASE!! :))

Capacitor Plot: Current Peak- 21.059 mA , 101.41 ms Voltage Peak- 167.681 V , 127.01 ms

Resistor Plot: Current Peak- 21.059 mA , 101.41 ms Voltage Peak- 21.071 V , 102.05 ms

A/C Source Plot: Current Peak- 21.059 mA , 101.41 ms Voltage Peak- 169 V , 125.09 ms

> Q5: How does the location of the current peak compare to the location of the voltage peak in each plot at 10 Hz? (Consider where the peaks occur in time.) (3) Create a copy of Table 9-1, and enter 5 frequency values between 10 and 100. Table 9-1. Data collection table for RC circuit with AC input. Calculated Xc Calculated Z Measured Vc Measured VR Measured Z Frequency (Hz) 10 100 Resistor: Capacitor: Supply Voltage: (4) Record the components used in the simulation. (5) Calculate the capacitive reactance, and total impedance for each frequency. (6) Record the peak voltage of the capacitor and resistor. > Q6: Do the peak voltages of each component add up to equal the peak voltage of the power source?

IGNORE THE TABLE 9-1

Answer 1

5. For the capacitor plot;

The current peak comes earlier than the voltage peak which you can see from plot is slight left to the voltage peak. Now this has to be true as a capacitor in ac current makes the voltage lag current which you can see is lagging the current. Also the peaks will occurs at a phase difference of 90 which means that the difference between both peak locations will be almost of 25ms which you can see from the data is same.

For the resister plot:

The voltage peak and the current peak comes at the same time,that is why they are overlapping each other in plot. This is because a resistor provides a resistive effect which just opposes its magnitude not direction. Thus the peak values might be different but peak locations will be same.

For the A/C plot:

Now since the whole circuit has a capacitance thus it will provide some negative reactance to the circuit which thus will provide a current which will be leading the voltage source which can be seen from the plot that the current peak is earlier than the voltage peak. Also the difference between the location of the peaks will be different from both resistive and reactive plot because it will be depending on both resistive and reactive part.

6. If you add the peak voltages of all the components you will get

Vsum = 167.681V + 21.071V = 188.752V

which is not equal to the peak voltage of the source. This is because resistance and reactance both act at a phase difference of 90. which means that they are not linear. Thus linear sum won't give you the peak source voltage.