Question

Inductor Plot: Current Peak- 622.161 mA , 104.155 ms (this is a data point for one of the peaks) Voltage Peak- 78.248 V , 101.275 ms (this is a data point for one of the peaks and at the top of each peak, the voltage matches that of the overall voltage of the inductor)

Resistor Plot: Current Peak- Nothing Voltage Peak- 62.268 V , 103.835 ms ( at the top of each peak, the voltage matches that of the overall voltage of the resistor)

A/C Source Plot: Current Peak- 622.677 mA , 93.915 ms Voltage Peak- 100 V , 92.635 ms ( at the top of each peak, the voltage matches that of the overall voltage of the A/C source)

Reset Run / STOP 200mH Simulation Speed Current Speed 0 Power Brightness Current Circuit: 100Hz 100 Get 50% Off Dedicated Hosting The Highest Level of Performance & Security Backed by the Most Helpful Humans in Hosting®. Liquid Web 78.248 V inductor 62.268 V resistor, 1000 100 V AC source t = 141.595 ms time step = 5 us

Inductor Plot: Voltage Peak- 12.4686 V , 102.165 ms Current Peak- 992.193 mA , 127.125 ms

Resistor Plot: Voltage Peak- 99.22 V , 126.805 ms Current Peak- Nothing

A/C Source Plot: Voltage Peak- 100 V , 124.885 ms Current Peak- 985.322 mA , 124.885 ms

Answer 1

11. In an ac circuit, if there is a reacting component like inductor or capacitor, then the current and the voltage will have different locations for their peak even if we consider the peaks occurring in time.

For the inductive plot;

The voltage peak comes earlier than the current peak which you can see from plot is slight left to the current peak. Now this has to be true as an inductor in ac current makes the voltage lead current which you can see is leading the current.

For the resistive plot:

The voltage peak and the current peak comes at the same time,that is why they are overlapping each other in plot. This is because a resistor provides a resistive effect which just opposes its magnitude not direction.

For the A/C plot:

Now since the whole circuit has an inductance thus it will provide a some positive reactance to the circuit which thus will provide a current which will be lagging the voltage source. As you can see that the peak of voltage comes earlier than that of the current peak, thus in plot voltage comes earlier than the current.

12. A capacitor provides a negative reactance while the inductance provides positive reactance. If a capacitor is added to a circuit it will lead the current over voltage which means that the current peak will come before the voltage peak while if an inductor is used it leads the voltage over current which means that the voltage peak will come before current peak. Also the reactance due to a capacitor is inversely proportional to the frequency while the reactance due to an inductor is proportional to the frequency.

10.

For the inductive plot;

The voltage peak comes earlier than the current peak which you can see from plot is slight left to the current peak. Now this has to be true as an inductor in ac current makes the voltage lead current which you can see is leading the current. Also if you compare with other plots like the resistive and the a/c plots you can see that the location of the peak are much farther than those of the other plots, this is because an inductor is a reactive component which leads voltage against current, even if the reactance is too low when compared to whole circuit still it will lead voltage sufficiently so that the peaks occur at an appreciable difference.

For the resistive plot:

The voltage peak and the current peak comes at the same time,that is why they are overlapping each other in plot. This is because a resistor provides a resistive effect which just opposes its magnitude not direction.

For the A/C plot:

Now since the whole circuit has an inductance thus it will provide some positive reactance to the circuit which thus will provide a current which will be lagging the voltage source. But from the peaks you can see they are very close to each other which means that the current is not lagging much as it was lagging at 100Hz. This is because of the reactance of the inductance, Since the reactance of an inductor is given as X_L = wL = 2$\pi$10Hz x 200mH = 12.556$\Omega$ which is much smaller than the resistance used. Thus the reactive part doesn't provides that much of lag to the current in the whole circuit and thus the peaks seem to be very close to each other.